Volts to kW Converter
Enter voltage, current, and power factor to calculate power in kilowatts (kW).
© Textile Calculator Ltd 2010-
Disclaimer: All calculators in the Textile Calculator have been reviewed by the relevant textile industry experts.
The Formula
kW = (Volts × Amps × Power Factor) ÷ 1,000
Or:
kW = (V × I × PF) / 1000
Table of Contents
A Volts to kW calculator does not allow direct conversion, because volts (V) and kilowatts (kW) measure different electrical quantities:
- Volts (V) measure electrical potential or voltage
- Kilowatts (kW) measure power (rate of energy use)
To convert volts to kilowatts, you must also know the current (amperes) and power factor (for AC systems).
Why You Can’t Convert Volts to kW Directly
Power (kW) depends on:
- Voltage (V)
- Current (A)
- Power Factor (PF) – in AC systems
So, you cannot get kW from volts alone. You need additional data.
How to Calculate kW from Volts – The Formula
For Single-Phase AC Systems:
✅ kW = (Volts × Amps × Power Factor) ÷ 1,000
Or:
kW = (V × I × PF) / 1000
For Three-Phase AC Systems:
✅ kW = (√3 × Volts × Amps × Power Factor) ÷ 1,000
Or:
kW = (1.732 × V × I × PF) / 1000
Where:
- V = voltage in volts
- I = current in amperes (A)
- PF = power factor (e.g., 0.8, 0.95)

Example Conversion (Single-Phase):
A sewing machine operates at 230 volts, draws 5 amps, with a power factor of 0.85 (single-phase):
kW = (230 × 5 × 0.85) ÷ 1000 = 977.5 ÷ 1000 = 0.9775 kW
So, the machine uses approximately 0.98 kW.
Example Conversion (Three-Phase):
A fabric dryer runs at 400 volts, draws 15 amps, with a power factor of 0.9 (three-phase):
kW = (1.732 × 400 × 15 × 0.9) ÷ 1000 = 9,352.8 ÷ 1000 = 9.35 kW
So, the dryer uses 9.35 kW of real power.

Use in Textile Engineering and Apparel Manufacturing
In textile processing:
- Machines are often labeled with voltage and current, but not power.
- Engineers calculate kW to determine energy use, cost, and load on electrical systems.
- This helps in:
- Sizing generators and transformers
- Performing energy audits
- Installing new equipment safely
By using the correct formula, professionals can:
- Estimate power consumption from nameplate data
- Compare machine efficiency
- Plan electrical load distribution
Importance of Accurate Power Calculation
Incorrect power estimation can lead to:
- Overloaded circuits
- Undersized cables or breakers
- High energy costs
- Equipment damage
Always verify voltage, current, and power factor before calculating kW.
Real-Life Examples
- Textile Loom:
Voltage = 220 V, Current = 8 A, PF = 0.85 (single-phase)
kW = (220 × 8 × 0.85) ÷ 1000 = 1,496 ÷ 1000 = 1.496 kW - Garment Factory Dryer:
Voltage = 415 V, Current = 20 A, PF = 0.9 (three-phase)
kW = (1.732 × 415 × 20 × 0.9) ÷ 1000 = 12,928 ÷ 1000 = 12.93 kW - Dyeing Plant Pump:
Voltage = 120 V, Current = 10 A, PF = 0.8 (single-phase)
kW = (120 × 10 × 0.8) ÷ 1000 = 960 ÷ 1000 = 0.96 kW
These examples show how kW is calculated from volts, amps, and PF in real textile applications.
Conclusion
This calculation is vital for engineers, technicians, and manufacturers working with electrical systems in textile production, machine installation, and energy management.
For more information on related topics, check out our articles on Ev to GeV Calculator and Electron Charge to Coulombs Calculator.
By mastering kW calculation from volts and current, you’ll enhance your ability to handle industrial power projects with confidence and precision.
