If you’re in the textile industry and need to calculate the production output of a comber machine, you’re in the right place. Comber machines play a crucial role in the spinning process, and understanding their production capacity is essential for efficient operations.

**Comber Machine Production Calculator**

Production:

## Table of Contents

Simply enter the values for the variables mentioned above into the calculator, and it will provide you with the production output.

Calculating the production of a comber machine is vital for optimizing your manufacturing process and achieving the desired efficiency.

**Production Calculation Formula for Comber Machine:**

The production for a single comber machine can be determined using the following formula:

**Production (For 1 Comber) **= (Nips/min × Feed/nip × Feed lap weight / Lap count × Time × No. of head × 100) – (Noil % / 100) × Efficiency

**Let’s define the variables used in this formula:**

**Nips/min**: The number of nips per minute.**Feed/nip:**The feed per nip.**Feed lap weight:**The weight of the feed lap.**Lap count:**The number of laps.**Time:**The time duration.**No. of head:**The number of comber machine heads.**Noil %:**The percentage of noil.**Efficiency:**The efficiency percentage.

Now, you can use the comber machine calculator to compute the production for a single comber machine.

Feel free to use the comber calculator to streamline your operations and improve your productivity.

**Comber Machine Calculation Math**

**1) Find out the production / day / comber in tons from the following parameters- **

Nips / min = 420,

Feed / nip = 6.5 mm = 6.5 / 25.4inch = 6.5 / 25.4 × 36 yds

Feed lap weight = 1150 grains / td = 1150 / 7000 lb / yd

Time = 24 hrs = (24 × 60)min

No. of head = 8

Noil % = 15

Efficiency = 90% = 0.9

**Production = 420 × 6.5 / 25.4 × 36 × 1150 / 7000 × ( 24 × 60) × 8 × 100 – 15 / 100 × 0.9**

= 4322.55 lbs / day

= 4322.55 / 2.2046 kg / day **[ 1 kg = 2.2046lbs]**

= 4322.55/2.2046× 1000 ton / day **[ 1 ton = 1000kg]**= 1.96 tons / day

**2. Calculate the production per shift of 8 combers from the following parameters –**

Nips / min = 430, Feed / nip = 5.5mm, Lap count = 100 gm / m

No. of head = 8, Noil % = 16%, Efficiency =90%

Here,

Nips / min = 430

Feed / nip = 5.5 mm = 5.5 / 1000m

Lap count = 100 gm / m = 100 / 1000 kg / m

Time = 1 shift = 8 hrs = (8 × 60 ) min

No. of head = 8

Noil % = 16

Efficiency = 90% = 0.9

No. of comber = 8

**Production = 8 [ 430 × 5.5 / 1000 × 100 / 1000 × ( 8 × 60 ) × 8 × 100 – 16 / 100 × 0.9**

= 5492.55 kg / shift

= ( 5492.55 × 2.2046)lb / shift.

= 12108.88 lb / shift

**3. Find out the production per shift from the following parameters –**

Nips / min = 450, Feed / nip = 6.3 mm, Lap count = 70 ktex,

Noil % = 18 %, No. of head = 8, Efficiency = 90%

Here,

Nips / min = 450

Feed / nip = 6.3 mm = 6.3 / 1000m

Lap count = 70 ktex = 70000 tex = 70000 / 1000 gm / m = 70 gm / m = 70 / 1000 kg / m

Time = 8 hrs = ( 8 × 60 ) min

No. of head = 8

Noil % = 18

Efficiency = 90% =0.9

**Production = 450 × 6.3 / 1000 × 70 / 1000 × ( 8 × 60 ) × 8 × 100-18 / 100 × 0.9**

=562.39 kg / shift.

**4. Calculate the production ( tons / day ) of 8 comber machines from the following parameters –**

Nips / min = 450, Feed / nip = 0.30, Lap hank = 0.018,

Noil % = 18%, Efficiency = 90%

Here,

Nips / min = 450

Feed / nip = 0.30 = 0.30/ 36 yds [ lyd = 36 inch]

Lap hank = 0.018 Ne = 1 / 0.018 × 840 lb / yds

Time = 24 hrs = ( 24 × 60 ) min

No. of head = 8

Noil % = 18

Efficiency = 90% =0.9

No. of comber = 8

**Production = 8 [ 450 × 0.30 / 36 × 1 / 0.018 × 840 × ( 24 × 60 ) × 8 × 100 -18 / 100 × 0.9**

= 16868.57 lbs / day

= 16868.57 / 2.2046 × 1000 tons / day [lkg = 2.2046 lbs, 1 ton = 1000 kg]

= 7.65 tons / day

**5. Find out the production of a comber in kg / shift (Assume all necessary parameters)**

By assuming,

Nips / min = 500

Feed / nip = 5 mm = 0.005 m

No. of head = 8

**Feed lap weight = 1150 grains / yd = 1150 / 7000 lb / yd = 1150 / 7000 × 2.2046 kg / yd**

= 1150 / 7000 × 2.2046 × 0.9144 kg / m

Noil % = 25

Efficiency = 90% =0.9

Time = 1 shift = 8 hrs = ( 8 × 60 )min

**Production = 500 × 0.005 × 1150 / 7000 × 2.2046 × 0.9144 × ( 8 × 60 ) × 8 × 100 – 25 / 100 × 0.9**

= 528 .09 kg / shift

**Standard Value – ( Math value assumed)**

- Nips/ min = 400 – 600
- Feed / nip = 4.3 – 7.5 mm
- Feed lap weight = 1150 – 1200 grains / yd
- No. of head = 8
- Noil % = 8 -25 %