Production:
Comber Production Formula
The production for a comber machine is calculated using the following formula:
Explanation of Variables:
- Nips/min: The number of nips per minute.
- Feed per Nip: The amount of fiber fed into the machine per nip.
- Lap Weight: The weight of the fiber lap being processed.
- Lap Count: The number of laps used in the calculation.
- Time: The duration of operation in minutes.
- No. of Heads: The number of combing heads in the machine.
- Efficiency: The machine efficiency in percentage.
- Noil%: The percentage of waste (noil) removed.
Note: The production is calculated in weight units (e.g., kg/hr) based on the given inputs.
If you’re in the textile industry and need to calculate the production output of a comber machine, you’re in the right place. Comber machines play a crucial role in the spinning process, and understanding their production capacity is essential for efficient operations.
Table of Contents
Simply enter the values for the variables mentioned above into the calculator, and it will provide you with the production output.
Calculating the production of a comber machine is vital for optimizing your manufacturing process and achieving the desired efficiency.
Production Calculation Formula for Comber Machine:

The production for a single comber machine can be determined using the following formula:
Production (For 1 Comber) = (Nips/min × Feed/nip × Feed lap weight / Lap count × Time × No. of head × 100) – (Noil % / 100) × Efficiency
Let’s define the variables used in this formula:
- Nips/min: The number of nips per minute.
- Feed/nip: The feed per nip.
- Feed lap weight: The weight of the feed lap.
- Lap count: The number of laps.
- Time: The time duration.
- No. of head: The number of comber machine heads.
- Noil %: The percentage of noil.
- Efficiency: The efficiency percentage.
Now, you can use the comber machine calculator to compute the production for a single comber machine.
Feel free to use the comber calculator to streamline your operations and improve your productivity.
Comber Machine Calculation Math
1) Find out the production / day / comber in tons from the following parameters-
Nips / min = 420,
Feed / nip = 6.5 mm = 6.5 / 25.4inch = 6.5 / 25.4 × 36 yds
Feed lap weight = 1150 grains / td = 1150 / 7000 lb / yd
Time = 24 hrs = (24 × 60)min
No. of head = 8
Noil % = 15
Efficiency = 90% = 0.9
Production = 420 × 6.5 / 25.4 × 36 × 1150 / 7000 × ( 24 × 60) × 8 × 100 – 15 / 100 × 0.9
= 4322.55 lbs / day
= 4322.55 / 2.2046 kg / day [ 1 kg = 2.2046lbs]
= 4322.55/2.2046× 1000 ton / day [ 1 ton = 1000kg]
= 1.96 tons / day
2. Calculate the production per shift of 8 combers from the following parameters –
Nips / min = 430, Feed / nip = 5.5mm, Lap count = 100 gm / m
No. of head = 8, Noil % = 16%, Efficiency =90%
Here,
Nips / min = 430
Feed / nip = 5.5 mm = 5.5 / 1000m
Lap count = 100 gm / m = 100 / 1000 kg / m
Time = 1 shift = 8 hrs = (8 × 60 ) min
No. of head = 8
Noil % = 16
Efficiency = 90% = 0.9
No. of comber = 8
Production = 8 [ 430 × 5.5 / 1000 × 100 / 1000 × ( 8 × 60 ) × 8 × 100 – 16 / 100 × 0.9
= 5492.55 kg / shift
= ( 5492.55 × 2.2046)lb / shift.
= 12108.88 lb / shift
3. Find out the production per shift from the following parameters –
Nips / min = 450, Feed / nip = 6.3 mm, Lap count = 70 ktex,
Noil % = 18 %, No. of head = 8, Efficiency = 90%
Here,
Nips / min = 450
Feed / nip = 6.3 mm = 6.3 / 1000m
Lap count = 70 ktex = 70000 tex = 70000 / 1000 gm / m = 70 gm / m = 70 / 1000 kg / m
Time = 8 hrs = ( 8 × 60 ) min
No. of head = 8
Noil % = 18
Efficiency = 90% =0.9
Production = 450 × 6.3 / 1000 × 70 / 1000 × ( 8 × 60 ) × 8 × 100-18 / 100 × 0.9
=562.39 kg / shift.
4. Calculate the production ( tons / day ) of 8 comber machines from the following parameters –
Nips / min = 450, Feed / nip = 0.30, Lap hank = 0.018,
Noil % = 18%, Efficiency = 90%
Here,
Nips / min = 450
Feed / nip = 0.30 = 0.30/ 36 yds [ lyd = 36 inch]
Lap hank = 0.018 Ne = 1 / 0.018 × 840 lb / yds
Time = 24 hrs = ( 24 × 60 ) min
No. of head = 8
Noil % = 18
Efficiency = 90% =0.9
No. of comber = 8
Production = 8 [ 450 × 0.30 / 36 × 1 / 0.018 × 840 × ( 24 × 60 ) × 8 × 100 -18 / 100 × 0.9
= 16868.57 lbs / day
= 16868.57 / 2.2046 × 1000 tons / day [lkg = 2.2046 lbs, 1 ton = 1000 kg]
= 7.65 tons / day
5. Find out the production of a comber in kg / shift (Assume all necessary parameters)
By assuming,
Nips / min = 500
Feed / nip = 5 mm = 0.005 m
No. of head = 8
Feed lap weight = 1150 grains / yd = 1150 / 7000 lb / yd = 1150 / 7000 × 2.2046 kg / yd
= 1150 / 7000 × 2.2046 × 0.9144 kg / m
Noil % = 25
Efficiency = 90% =0.9
Time = 1 shift = 8 hrs = ( 8 × 60 )min
Production = 500 × 0.005 × 1150 / 7000 × 2.2046 × 0.9144 × ( 8 × 60 ) × 8 × 100 – 25 / 100 × 0.9
= 528 .09 kg / shift
Standard Value – ( Math value assumed)
- Nips/ min = 400 – 600
- Feed / nip = 4.3 – 7.5 mm
- Feed lap weight = 1150 – 1200 grains / yd
- No. of head = 8
- Noil % = 8 -25 %
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